Răspuns:
11) a) -33[tex]\sqrt{2}[/tex]
9 nu se vede în poză
Explicație pas cu pas:
[tex]33\sqrt{3} - (\frac{15}{2\sqrt{3} } +\frac{12}{5\sqrt{2} } )*10\sqrt{6}-(\frac{3}{2\sqrt{8} } -\frac{5}{3\sqrt{12} } )*12\sqrt{6} +32\sqrt{2} \\\\RATIONALIZAM\\ 33\sqrt{3} - (\frac{5\sqrt{3}}{2} +\frac{6\sqrt{2}}{5} )*10\sqrt{6}-(\frac{3\sqrt{2}}{8} -\frac{5\sqrt{3}}{18} )*12\sqrt{6} +32\sqrt{2}\\\\33\sqrt{3} - ({25\sqrt{18} +{12\sqrt{12}} )-(\frac{9\sqrt{12}}{2} -\frac{10\sqrt{18}}{3} ) +32\sqrt{2}[/tex]
[tex]33\sqrt{3} - ({75\sqrt{2} +{24\sqrt{3}} )-(\frac{18\sqrt{3}}{2} -\frac{30\sqrt{2}}{3} ) +32\sqrt{2} \\ \\ \\[/tex]
[tex]33\sqrt{3} - {75\sqrt{2} -{24\sqrt{3}} -{9\sqrt{3}} +{10\sqrt{2}} +32\sqrt{2}[/tex]
[tex]75\sqrt{3} - 108\sqrt{3} = - 33\sqrt{3}[/tex]
b)
[tex]6(3\sqrt{2}-2\sqrt{3} )-(\frac{18}{\sqrt{27} } +\frac{20}{\sqrt{50} } )*2\sqrt{6} -(\frac{5}{\sqrt{75} }-\frac{10}{\sqrt{8} } )*3\sqrt{6} \\ \\ 18\sqrt{2}-12\sqrt{3}-\frac{18}{3\sqrt{3} } +\frac{20}{5\sqrt{2} } )*2\sqrt{6}-(\frac{5}{5\sqrt{3} }-\frac{10}{2\sqrt{2} } )*3\sqrt{6}\\ \\ 18\sqrt{2}-12\sqrt{3}-\frac{6}{\sqrt{3} } +\frac{4}{\sqrt{2} } )*2\sqrt{6}-(\frac{1}{\sqrt{3} }-\frac{5}{\sqrt{2} })*3\sqrt{6}\\ \\ RATIONALIZAM[/tex]
[tex]\\ \\ 18\sqrt{2} - 12\sqrt{3} - ( 2\sqrt{3} + 2\sqrt{2} )*2\sqrt{6}-(\frac{\sqrt{3}}{3} -\frac{5\sqrt{2}}{2} )*3\sqrt{6} \\ \\ 18\sqrt{2} - 12\sqrt{3} - ( 4\sqrt{18} - 4\sqrt{12} )-(\sqrt{18}-\frac{15\sqrt{12} }{2} )\\ \\ 18\sqrt{2} - 12\sqrt{3} - ( 12\sqrt{2} + 8\sqrt{3} )-(3\sqrt{2} - \frac{30\sqrt{3} }{2})\\ \\ 18\sqrt{2} - 12\sqrt{3} - 12\sqrt{2} - 8\sqrt{3}- 3\sqrt{2} + 15\sqrt{3}[/tex]
[tex]3\sqrt{2}-5\sqrt{3}[/tex]
