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Calculati:
A) √432×(√726-√486+√294-√600)+120√2
B) √162×(√75-√147+√48-√300)+ 12√24


Răspuns :

Răspuns:

Explicație pas cu pas:

Vezi imaginea LAURA

Răspuns:

[tex]A=84\sqrt{2}[/tex]

[tex]B=-48\sqrt{6}[/tex]

Explicație pas cu pas:

[tex]\sqrt{432} *(\sqrt{726} -\sqrt{486} +\sqrt{294} -\sqrt{600} )+120\sqrt{2} =[/tex]

[tex]12\sqrt{3} *(11\sqrt{6} -9\sqrt{6} +7\sqrt{6} -10\sqrt{6} )+120\sqrt{2} =[/tex]

[tex]12\sqrt{3} *[(11-9+7-10)\sqrt{6} ]+120\sqrt{2} =[/tex]

[tex]12\sqrt{3} *(-\sqrt{6} )+120\sqrt{2} =[/tex]

[tex]-12\sqrt{18} +120\sqrt{2} =[/tex]

[tex]-12*3\sqrt{2}+120\sqrt{2} =[/tex]

[tex]-36\sqrt{2} +120\sqrt{2} =[/tex]

[tex]84\sqrt{2}[/tex]

[tex]\sqrt{162} *(\sqrt{75} -\sqrt{147} +\sqrt{48} -\sqrt{300} )+12\sqrt{24} =[/tex]

[tex]9\sqrt{2} *(5\sqrt{3} -7\sqrt{3} +4\sqrt{3} -10\sqrt{3} )+12\sqrt{24} =[/tex]

[tex]9\sqrt{2} *[(5-7+4-10)\sqrt{3} ]+12*2\sqrt{6} =[/tex]

[tex]9\sqrt{2} *(-8\sqrt{3} )+24\sqrt{6} =[/tex]

[tex]-72\sqrt{6} +24\sqrt{6} =[/tex]

[tex]-48\sqrt{6}[/tex]