[tex]2AB=3BC=>AB=\frac{3}{2}BC\\ 3BC=4AC=>AC=\frac{3}{4}BC\\ P=AB+BC+AC=\frac{3}{2}BC+BC+\frac{3}{4}BC=\frac{6}{4}BC+\frac{4}{4}BC+\frac{3}{4}BC=\frac{13}{4}BC=>BC=\frac{4P}{13}=\frac{4*52}{13}=\frac{208}{13}=16 cm\\ BC=16 cm[/tex]
[tex]AB=\frac{3}{2}BC=\frac{3*16}{2}=3*8=24 cm=>AB=24 cm\\ AC=\frac{3}{4}BC=\frac{3*16}{4}=3*4=12 cm=>AC=12 cm[/tex]