[tex]\it 2,(6)=2\dfrac{\ \ 6^{(3}}{9}=2\dfrac{2}{3}=\dfrac{8}{3}\\ \\ \\ 3,1(3)=3\dfrac{13-1}{90}=3\dfrac{\ \ 12^{(6}}{90}=3\dfrac{2}{15}=\dfrac{47}{15}\\ \\ \\ 9\dfrac{2}{5}=\dfrac{47}{5}[/tex]
Acum, exercițiul devine :
[tex]\it \Big(2,6-\dfrac{8}{3}\cdot\dfrac{3}{4}\Big):\Big(\dfrac{47}{15}:\dfrac{47}{5}+\dfrac{1}{6}\Big)=(2,6-2):\Big(\dfrac{47}{15}\cdot\dfrac{5}{47}+\dfrac{1}{6}\Big)=\\ \\ \\ =0,6:\Big(\dfrac{^{2)}1}{\ 3}+\dfrac{1}{6}\Big)=0,6:\dfrac{\ 3^{(3}}{6}=0,6:\dfrac{1}{2}=0,6:0,5=6:5=1,2[/tex]
