Răspuns:
x ∈ [1/2 ; 2/3]
Explicație pas cu pas:
(3x-2)(2x-1) ≤0 <=>
6x² -3x-4x +2 ≤ 0 <=>
6x² -7x +2 ≤ 0
6x²-7x+2 = 0 ; a = 6 ; b = -7 ; c = 2
Δ = b²-4ac = 49-4·6·2 = 49-48 = 1
√Δ = 1
x₁,₂ = (-b±√Δ)/2a = (7±1)/12
x₁ = (7-1)/12 = 6/12 = 1/2
x₂ = (7+1)/12 = 8/12 = 2/3
6x² -7x +2 ≤ 0 => x ∈ [1/2 ; 2/3]
#copaceibranly
