Răspuns:
Explicație:
ms= 240 g sol. HCl
c=10%
CaCO3
masa de sare formata
-se afla md sol. de HCl
md= c.ms : 100
md= 10 .240 : 100= 24g HCl
xg 24g yg
CaCO3 +2 HCl= CaCl2 + CO2 + H2O
100g 2.36,5g 111g
x= 24.100 : 73= 32,87 g CaCO3
y= 24 . 111 : 73= 36,49g CaCl2
MCaCO3= 40 +12 +3.16=100-----> 100g/moli
M Cacl2= 40 + 2.35,5=111------> 111g/moli