Răspuns:
v=ma+nb m,n∈R
ma=5mi+3mj
nb=-2ni+3nj
3i-2j=5mi+3mj-2ni+3j
3i-2j=(5mi-2ni)+(3mj+3j)
3i-2j=(5m-2n)i+3(m+n)j=.>
Sistem
{5m-2n=3
{3(m+n)= -2<=>3m+3n= -2
Inmultesti prima ecuatie 3 ,pe a 2-a cu- 5 si le adui
15m-6n-15m-15n=9+10
-21n=19
n= -19/21
inlocuiesti pe n= -19/21 in prima ecuatie si aflii pe m
5m-2*19/21=3
5m=3+38/21
5m=(63+38)/21
5m=101/21
m=101/21:5=101/105
v=101/105i-19/21j
Explicație pas cu pas:
