Răspuns:
Explicație pas cu pas:
a) 3a-3b = 3(a-b)
c) 9a-6b = 3(3a-2b)
e) 3a²-6ab+9 = 3(a²-2ab+3)
g) 10a+5b+25 = 5(2a+b+5)
i) x²y+xy² = xy(x+y)
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b) 3x²+3 = 3(x²+1)
d) 12a²+9 = 3(4a²+3)
f) 4x-6y = 2(2x-3y)
h) xy+xy²-3x = x(y+y²-3)
j) 2a²b+3ab²-5a³b = ab(2a+3b-5a²)
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k) 4a+8a²-12ab³ = 4a(1+2a-3b³)
l) a(x+1)+b(x+1)+c(x+1) = (x+1)(a+b+c)
m) ab(x-1)-b²(x-1) = (x-1)(ab-b²) = b(x-1)(a-b)
n) 2(x+3)-5(x+3) = (x+3)(2-5) = (-3)(x+3)
o) 3x(1-x)+4(1-x) = (1-x)(3x+4)
p) x³y²-2xy⁵+x²y = xy(x²y-2y⁴+x)
q) (2x-5)(x+7)+(2x-5)(5x-3) = (2x-5)(x+7+5x-3) = (2x-5)(6x+4) =
= 2(2x-5)(3x+2)
