Răspuns:
Zn + H2SO4---> ZnSO4 + H2 reactie de inlocuire
mZn,impur=290g
p=94%
p=m,px100/m,i---> m,p= 290x94/100g=272,6g ZnPUR
eta(randamentul)=96%
DIN ecuatia chimica
1molZn.........1molZnSO4 SAU, IN GRAME
65g.................161g
272,6g...........x
x=m,teoretic=675,2gZnSO4
m,practic=675,2x96/100g=648,2g ZnSO4
am folosit: A,Zn=65g/mol miuZnSO4=161g/mol
Explicație: