Dacă a)
[tex] {(a - 3})^{2} + {(b + 4)}^{2} - 4 = 0 = > {(a - 3)}^{2} + {(b + 4)}^{2} = 4[/tex]
a-3=2. b+4=0=>a=5,b=-4
a-3=0. b+4=2=>a=3,b=-2
=>a>b
B) a+3=0. b-5=2=>a=-3,b=7
a+3=2. b-5=0=>a=-1,b=5
a<b
C)a-5=0. b+4=2=>a=5,b=-2
a-5=2. b+4=0=>a=7,b=-4
a>b
D) a+2=2. b-4=0=>a=2,b=4
a+2=0. b-4=2=>a=-2,b=6
a<b
