Răspuns:
Explicație pas cu pas:
6. a. f(x)=-x-5
A(3m, 2m-9) ∈ Gf ⇔ f(3m)=2m-9
-3m-5=2m-9, 5m=4, m=4/5
b.
[tex]f(\sqrt{2})= -\sqrt{2}-5\\ f(-\sqrt{2})=\sqrt{2}-5\\[/tex]
[tex]m_{a}=\frac{-\sqrt{2}-5+\sqrt{2}-5 }{2}=\frac{-10}{2}=-5[/tex]
[tex]m_{g}=\sqrt{(-\sqrt{2}-5 )(\sqrt{2}-5 )} =\sqrt{23}[/tex]
7.
f(x)=-3x+2
f(2x)=-6x+2, f(-1)=5, f(-x)=3x+2, f(2/3)=0
[tex]\frac{-3x+2+4}{2}+5=3x+2[/tex]
-3x+6+10=6x+4
9x=12, x=4/3
