Răspuns:
1. MH2 =2×1=2g
MNH3 =14+3=17g/mol
3×2g 2×17g
N2+ 3H2=> 2 NH3
xg 34g
x=34×3×2/2×17= calculează
2.
MH2 =2×1=2g/mol
MHCl =1+35,5=36,5g/mol
2g 2×36,5g
H2+ Cl2 => 2HCl
26g xgH
x=26×2×36,5/2= calculează
3.
MFe =56g/mol
MFe2O3 =2×56+3×16=160g/mol
4×56g 2×160g
4Fe + 3O2 =>2 Fe2O3
168g ygFe2O3
y=168×2×160/4×56= calculează
4. MCaO=40+16=56g/mol
MHCl=1+35,5=36,5g/mol
56g 2×36,5g
CaO + 2HCl => CaCl2 + H2O
20g zgHCl
z=20×2×36,5/56=calculează
5.
MMg =24g/mol
MMgO =24+16=40g /mol
2×24g 2×40g
2Mg + O2=> 2MgO
xgMg 80g
x=80×2×24/2×40=calculează.
